std::_Exit

 

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Defined in header <cstdlib>
[[noreturn]] void _Exit( int exit_code ) noexcept;		(since C++11)

Causes normal program termination to occur without completely cleaning the resources.

Destructors of variables with automatic, thread local and static storage durations are not called. Functions passed to std::at_quick_exit() or std::atexit() are not called. Whether open resources such as files are closed is implementation defined.

If exit_code is 0 or EXIT_SUCCESS, an implementation-defined status indicating successful termination is returned to the host environment. If exit_code is EXIT_FAILURE, an implementation-defined status, indicating unsuccessful termination, is returned. In other cases implementation-defined status value is returned.

Parameters

exit_code

-

exit status of the program

Return value

(none)

Example

Run this code

#include <iostream>
 
class Static {
public:
    ~Static() 
    {
        std::cout << "Static dtor\n";
    }
};
 
class Local {
public:
    ~Local() 
    {
        std::cout << "Local dtor\n";
    }
};
 
Static static_variable; // dtor of this object will *not* be called
 
void atexit_handler()
{
    std::cout << "atexit handler\n";
}
 
int main()
{
    Local local_variable; // dtor of this object will *not* be called
 
    // handler will *not* be called
    const int result = std::atexit(atexit_handler);
 
    if (result != 0) {
        std::cerr << "atexit registration failed\n";
        return EXIT_FAILURE;
    }
 
    std::cout << "test" << std::endl; // flush from std::endl
        // needs to be here, otherwise nothing will be printed
    std::_Exit(EXIT_FAILURE);
}

Output:

test

See also

abort	causes abnormal program termination (without cleaning up) (function)
exit	causes normal program termination with cleaning up (function)