std::move_backward
From cppreference.com
Defined in header <algorithm>
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template< class BidirIt1, class BidirIt2 > BidirIt2 move_backward( BidirIt1 first, BidirIt1 last, BidirIt2 d_last ); |
(since C++11) (until C++20) |
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template< class BidirIt1, class BidirIt2 > constexpr BidirIt2 move_backward( BidirIt1 first, BidirIt1 last, BidirIt2 d_last ); |
(since C++20) | |
Moves the elements from the range [first, last)
, to another range ending at d_last
. The elements are moved in reverse order (the last element is moved first), but their relative order is preserved.
The behavior is undefined if d_last
is within (first, last]
. std::move must be used instead of std::move_backward
in that case.
Parameters
first, last | - | the range of the elements to move |
d_last | - | end of the destination range |
Type requirements | ||
-BidirIt1, BidirIt2 must meet the requirements of LegacyBidirectionalIterator.
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Return value
Iterator in the destination range, pointing at the last element moved.
Complexity
Exactly last - first
move assignments.
Possible implementation
template< class BidirIt1, class BidirIt2 > BidirIt2 move_backward(BidirIt1 first, BidirIt1 last, BidirIt2 d_last) { while (first != last) { *(--d_last) = std::move(*(--last)); } return d_last; } |
Notes
When moving overlapping ranges, std::move
is appropriate when moving to the left (beginning of the destination range is outside the source range) while std::move_backward
is appropriate when moving to the right (end of the destination range is outside the source range).
Example
Run this code
#include <algorithm> #include <vector> #include <string> #include <iostream> int main() { std::vector<std::string> src{"foo", "bar", "baz"}; std::vector<std::string> dest(src.size()); std::cout << "src: "; for (const auto &s : src) { std::cout << s << ' '; } std::cout << "\ndest: "; for (const auto &s : dest) { std::cout << s << ' '; } std::cout << '\n'; std::move_backward(src.begin(), src.end(), dest.end()); std::cout << "src: "; for (const auto &s : src) { std::cout << s << ' '; } std::cout << "\ndest: "; for (const auto &s : dest) { std::cout << s << ' '; } std::cout << '\n'; }
Output:
src: foo bar baz dest: src: dest: foo bar baz
See also
(C++11) |
moves a range of elements to a new location (function template) |